How do I calculate the voltage drop over wires given a supply voltage and a current? How do I anticipate on voltage drop so that the final load has the correct supply voltage? What will be the power

Power lost in the wires is 60² * 0.01 = 36 watts so energy delivered is this number multiplied by time (2 seconds) = 72 joules. Why can I use P = I²R but not P=V²/R when calculating energy lost in a circuit?

I was wondering Where I could find the derivation for the complex power formula, S=VI*/2, where S, V and I are complex phasors. I've seen a whole bunch of verifications where people sub stuff into...

Jan 20, 2021 · Yes, because I is a function of V, as long as we're talking about resistors. Power is linearly proportional to voltage, though, if you're talking about a constant current device.

Jun 18, 2016 · The voltage in that formula must be the one across the load or subject of which you are interested to calculate the power, and the R is the resistance of that subject.

May 1, 2016 · The basic formula for power is just like P = V.I except it is: - Power = pressure (pascals) x flow rate (cubic metres per second) To calculate flow rate needed to deliver 10 kW, divide power by …

Electrical power is the product of voltage and current: $$ P = VI $$ Usually we are converting electrical energy into heat, and we care about power because we don't want to melt our components. It doesn't …

The main power draw in CPU's is caused by the charging and discharging of capacitors during calculations. These electrical charges are dissipated in resistors, turning the associated electrical …

Phase 3 (V): 245.9375V I will like to know what is the total current generated, as well as the voltage value. Additionally, I want to find the power too. What I am thinking is that the 3-phase current and …

The first formula you give above is correct. You find the instantaneous power as a function of time, integrate over the time interval of interest, and divide by the length of that interval. For a time-varying …